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The Advanced Numeracy Test Workbook - Mike Bryon [42]

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Q12. Answer A.

Explanation The average wage = $42,000,000 ÷ 2,000 = 21,000. 21,000 × 5% = 1,050. The training budget divided by the total number of employees = $1,260,000 ÷ 2,000 = $630. $1,050 – $630 = $420.

Q13. Answer C.

Explanation $180,500 was spent on the Effective e-mails module at $475 per delegate. 180,500 ÷ 475 = 380. Therefore 380 people attended the module which lasted 1 day, so 380 days were lost.

Q14. Answer B.

Explanation The data set states that 60% of staff and associated costs shown relate to staff in sales positions. Therefore the total cost to Training Unlimited for sales staff identified in the data = 60% of the international wage bill plus 60% of the personal development budget = $42,000,000 + $1,260,000 = $43,260,000 × 60% = $25,956,000. Note that it is wrong to calculate the total cost as 105% of $42,000,000 as the total spent on personal development (given in the last table in the data set) is shown as $1,260,000.

Q15. Answer D.

Explanation It is stated that 60% of staff and associated costs shown relate to staff in sales positions. It can be calculated that 1,200 staff (60% of all staff) attended the Closing a sale module which is only open to sales staff, but it is not known what percentage of the total staff are in sales positions. Therefore it cannot be calculated what percentage of the total sales staff is represented by the 1,200 staff who attended this module.

Q16. Answer C.

Explanation All staff may spend to a maximum of 5% of the average wage on personal development = $1,050. Sales staff may attend the two modules Public speaking and Closing a sale, which total 3 days at a combined cost of £300. They can also attend the Personal safety day at $150, giving a subtotal of 4 days and $450 spent. This leaves $600 of their budget but they can only afford the modules Dealing with conflict or Effective e-mails, both at $475 and lasting 1 day. Therefore the theoretical maximum number of days = 5.

Q17. Answer A.

Explanation The total spend on the demonstrating leadership module was $182,000 at a cost of $350 a delegate. $182,000 ÷ $350 = 520, so there were 520 delegates in total, of whom one in four was a woman. 520 ÷ 4 = 130 women. Calculate 130 as a percentage of the total workforce (2,000). 100% = 2,000, 1% = 0.05 × 130 = 6.5%.

Q18. Answer D.

Explanation Both a manager and a member of the sales team can attend the Personal safety module ($150) and either Effective e-mails or Dealing with conflict (both of which cost $475). Only a manager can attend the Demonstrating leadership module ($350), and only a member of the sales team can attend Public speaking and Closing a sale ($300). To attend a total of 5 days’ training therefore the manager must spend $50 more than a member of the sales team.

Q19. Answer B.

Explanation The budget is set at $1,260,000 and it is clear from the cost table that this was the sum spent. If you selected 60% then you mistakenly calculated the sum of all the personal development values of 2,000 staff at $1,050 a year and found that the spend equalled 60% of this. But this is not the budget.

Q20. Answer D.

Explanation Suggested answer A might appear as if it would save $180,500 at a cost of 380 days’ training but it alone would not lead to a cut in the budget because staff could still elect to spend this money by going on other courses. Suggested answer C would fail to secure a cut of 14.3% as $180,000 is $180 less than 14.3% of $1,260,000 and also would not prevent staff from attending other courses.

Q21. Answer B.

Explanation The number of dollar millionaires in 2009 is described as 6% up on the 2008 figure. The 2009 figure of 10,249,988 = 106% of the 2008 figure. Divide 10,249,988 by 106 = 96,698 (= 1%) and multiply by 100 to get the 2008 figure.

Q22. Answer C.

Explanation Find the highest yearly income and subtract the lowest. The highest yearly income is found in Ethiopia = $123 × 79 million = $9,717,000. The lowest yearly income is earned in Somalia $168 × 8.5 million = $1,428,000, so the difference is

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